Distance from Dix Hills to Zonnebeke
The shortest distance (air line) between Dix Hills and Zonnebeke is 3,571.73 mi (5,748.15 km).
How far is Dix Hills from Zonnebeke
Dix Hills is located in New York, United States within 40° 48' 11.88" N -74° 39' 45" W (40.8033, -73.3375) coordinates. The local time in Dix Hills is 18:48 (01.02.2025)
Zonnebeke is located in Arr. Ieper, Belgium within 50° 52' 0.12" N 2° 58' 59.88" E (50.8667, 2.9833) coordinates. The local time in Zonnebeke is 00:48 (02.02.2025)
The calculated flying distance from Zonnebeke to Zonnebeke is 3,571.73 miles which is equal to 5,748.15 km.
Dix Hills, New York, United States
Related Distances from Dix Hills
Zonnebeke, Arr. Ieper, Belgium