Distance from Doctor Phillips to Asenovgrad
The shortest distance (air line) between Doctor Phillips and Asenovgrad is 5,682.87 mi (9,145.69 km).
How far is Doctor Phillips from Asenovgrad
Doctor Phillips is located in Florida, United States within 28° 26' 50.64" N -82° 30' 30.96" W (28.4474, -81.4914) coordinates. The local time in Doctor Phillips is 13:35 (24.11.2024)
Asenovgrad is located in Plovdiv, Bulgaria within 42° 1' 0.12" N 24° 52' 0.12" E (42.0167, 24.8667) coordinates. The local time in Asenovgrad is 20:35 (24.11.2024)
The calculated flying distance from Asenovgrad to Asenovgrad is 5,682.87 miles which is equal to 9,145.69 km.
Doctor Phillips, Florida, United States