Distance from Doctor Phillips to Diepenbeek
The shortest distance (air line) between Doctor Phillips and Diepenbeek is 4,591.00 mi (7,388.51 km).
How far is Doctor Phillips from Diepenbeek
Doctor Phillips is located in Florida, United States within 28° 26' 50.64" N -82° 30' 30.96" W (28.4474, -81.4914) coordinates. The local time in Doctor Phillips is 04:16 (24.11.2024)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 10:16 (24.11.2024)
The calculated flying distance from Diepenbeek to Diepenbeek is 4,591.00 miles which is equal to 7,388.51 km.
Doctor Phillips, Florida, United States
Related Distances from Doctor Phillips
Diepenbeek, Arr. Hasselt, Belgium