Distance from Doctor Phillips to Sint-Andries
The shortest distance (air line) between Doctor Phillips and Sint-Andries is 4,492.14 mi (7,229.40 km).
How far is Doctor Phillips from Sint-Andries
Doctor Phillips is located in Florida, United States within 28° 26' 50.64" N -82° 30' 30.96" W (28.4474, -81.4914) coordinates. The local time in Doctor Phillips is 16:02 (17.02.2025)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 22:02 (17.02.2025)
The calculated flying distance from Sint-Andries to Sint-Andries is 4,492.14 miles which is equal to 7,229.40 km.
Doctor Phillips, Florida, United States
Related Distances from Doctor Phillips
Sint-Andries, Arr. Brugge, Belgium