Distance from Doctor Phillips to Sveti Ivan Zelina
The shortest distance (air line) between Doctor Phillips and Sveti Ivan Zelina is 5,176.48 mi (8,330.74 km).
How far is Doctor Phillips from Sveti Ivan Zelina
Doctor Phillips is located in Florida, United States within 28° 26' 50.64" N -82° 30' 30.96" W (28.4474, -81.4914) coordinates. The local time in Doctor Phillips is 23:27 (08.04.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 05:27 (09.04.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 5,176.48 miles which is equal to 8,330.74 km.
Doctor Phillips, Florida, United States
Related Distances from Doctor Phillips
Sveti Ivan Zelina, Zagrebačka županija, Croatia