Distance from Drobeta-Turnu Severin to Aleksandrow Kujawski
The shortest distance (air line) between Drobeta-Turnu Severin and Aleksandrow Kujawski is 597.16 mi (961.04 km).
How far is Drobeta-Turnu Severin from Aleksandrow Kujawski
Drobeta-Turnu Severin is located in Mehedinţi, Romania within 44° 37' 59.88" N 22° 38' 60" E (44.6333, 22.6500) coordinates. The local time in Drobeta-Turnu Severin is 01:00 (24.05.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 00:00 (24.05.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 597.16 miles which is equal to 961.04 km.
Drobeta-Turnu Severin, Mehedinţi, Romania
Related Distances from Drobeta-Turnu Severin
Aleksandrow Kujawski, Włocławski, Poland