Distance from Druskininkai to Jacksonville
The shortest distance (air line) between Druskininkai and Jacksonville is 5,128.20 mi (8,253.04 km).
How far is Druskininkai from Jacksonville
Druskininkai is located in Alytaus apskritis, Lithuania within 54° 1' 0.12" N 23° 58' 0.12" E (54.0167, 23.9667) coordinates. The local time in Druskininkai is 18:35 (03.03.2025)
Jacksonville is located in Florida, United States within 30° 19' 55.92" N -82° 19' 30.36" W (30.3322, -81.6749) coordinates. The local time in Jacksonville is 11:35 (03.03.2025)
The calculated flying distance from Jacksonville to Jacksonville is 5,128.20 miles which is equal to 8,253.04 km.
Druskininkai, Alytaus apskritis, Lithuania
Related Distances from Druskininkai
Jacksonville, Florida, United States