Distance from Dunwoody to Sveti Ivan Zelina
The shortest distance (air line) between Dunwoody and Sveti Ivan Zelina is 5,029.92 mi (8,094.88 km).
How far is Dunwoody from Sveti Ivan Zelina
Dunwoody is located in Georgia, United States within 33° 56' 30.48" N -85° 41' 16.08" W (33.9418, -84.3122) coordinates. The local time in Dunwoody is 12:12 (15.03.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 18:12 (15.03.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 5,029.92 miles which is equal to 8,094.88 km.
Dunwoody, Georgia, United States
Related Distances from Dunwoody
Sveti Ivan Zelina, Zagrebačka županija, Croatia