Distance from East Patchogue to Cesky Tesin
The shortest distance (air line) between East Patchogue and Cesky Tesin is 4,215.40 mi (6,784.02 km).
How far is East Patchogue from Cesky Tesin
East Patchogue is located in New York, United States within 40° 46' 13.44" N -73° 1' 5.88" W (40.7704, -72.9817) coordinates. The local time in East Patchogue is 03:12 (11.02.2025)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 09:12 (11.02.2025)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 4,215.40 miles which is equal to 6,784.02 km.
East Patchogue, New York, United States
Related Distances from East Patchogue
Cesky Tesin, Moravskoslezský kraj, Czechia