Distance from East Patchogue to Wallenhorst
The shortest distance (air line) between East Patchogue and Wallenhorst is 3,723.03 mi (5,991.64 km).
How far is East Patchogue from Wallenhorst
East Patchogue is located in New York, United States within 40° 46' 13.44" N -73° 1' 5.88" W (40.7704, -72.9817) coordinates. The local time in East Patchogue is 15:15 (02.03.2025)
Wallenhorst is located in Osnabrück; Landkreis, Germany within 52° 21' 0" N 8° 1' 0.12" E (52.3500, 8.0167) coordinates. The local time in Wallenhorst is 21:15 (02.03.2025)
The calculated flying distance from Wallenhorst to Wallenhorst is 3,723.03 miles which is equal to 5,991.64 km.
East Patchogue, New York, United States
Related Distances from East Patchogue
Wallenhorst, Osnabrück; Landkreis, Germany