Distance from Eden Prairie to Sveti Ivan Zelina
The shortest distance (air line) between Eden Prairie and Sveti Ivan Zelina is 4,841.66 mi (7,791.91 km).
How far is Eden Prairie from Sveti Ivan Zelina
Eden Prairie is located in Minnesota, United States within 44° 50' 55.68" N -94° 32' 25.8" W (44.8488, -93.4595) coordinates. The local time in Eden Prairie is 00:04 (02.02.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 07:04 (02.02.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 4,841.66 miles which is equal to 7,791.91 km.
Eden Prairie, Minnesota, United States
Related Distances from Eden Prairie
Sveti Ivan Zelina, Zagrebačka županija, Croatia