Distance from Essex Junction to Janow Lubelski
The shortest distance (air line) between Essex Junction and Janow Lubelski is 4,150.65 mi (6,679.83 km).
How far is Essex Junction from Janow Lubelski
Essex Junction is located in Vermont, United States within 44° 29' 24.72" N -74° 53' 9.24" W (44.4902, -73.1141) coordinates. The local time in Essex Junction is 07:34 (01.03.2025)
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 13:34 (01.03.2025)
The calculated flying distance from Janow Lubelski to Janow Lubelski is 4,150.65 miles which is equal to 6,679.83 km.
Essex Junction, Vermont, United States
Related Distances from Essex Junction
Janow Lubelski, Puławski, Poland