Distance from Evansville to Aleksandrovac
The shortest distance (air line) between Evansville and Aleksandrovac is 5,254.91 mi (8,456.95 km).
How far is Evansville from Aleksandrovac
Evansville is located in Indiana, United States within 37° 59' 17.16" N -88° 27' 57.24" W (37.9881, -87.5341) coordinates. The local time in Evansville is 19:32 (08.03.2025)
Aleksandrovac is located in Rasinska oblast, Serbia within 43° 27' 19.08" N 21° 3' 5.04" E (43.4553, 21.0514) coordinates. The local time in Aleksandrovac is 02:32 (09.03.2025)
The calculated flying distance from Aleksandrovac to Aleksandrovac is 5,254.91 miles which is equal to 8,456.95 km.
Evansville, Indiana, United States
Related Distances from Evansville
Aleksandrovac, Rasinska oblast, Serbia