Distance from Evansville to Aleksandrow Lodzki
The shortest distance (air line) between Evansville and Aleksandrow Lodzki is 4,833.66 mi (7,779.02 km).
How far is Evansville from Aleksandrow Lodzki
Evansville is located in Indiana, United States within 37° 59' 17.16" N -88° 27' 57.24" W (37.9881, -87.5341) coordinates. The local time in Evansville is 21:48 (03.03.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 04:48 (04.03.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 4,833.66 miles which is equal to 7,779.02 km.
Evansville, Indiana, United States
Related Distances from Evansville
Aleksandrow Lodzki, Łódzki, Poland