Distance from Evansville to Begijnendijk
The shortest distance (air line) between Evansville and Begijnendijk is 4,333.28 mi (6,973.75 km).
How far is Evansville from Begijnendijk
Evansville is located in Indiana, United States within 37° 59' 17.16" N -88° 27' 57.24" W (37.9881, -87.5341) coordinates. The local time in Evansville is 08:17 (01.02.2025)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 15:17 (01.02.2025)
The calculated flying distance from Begijnendijk to Begijnendijk is 4,333.28 miles which is equal to 6,973.75 km.
Evansville, Indiana, United States
Related Distances from Evansville
Begijnendijk, Arr. Leuven, Belgium