Distance from Evansville to Boguszow-Gorce
The shortest distance (air line) between Evansville and Boguszow-Gorce is 4,767.29 mi (7,672.21 km).
How far is Evansville from Boguszow-Gorce
Evansville is located in Indiana, United States within 37° 59' 17.16" N -88° 27' 57.24" W (37.9881, -87.5341) coordinates. The local time in Evansville is 22:36 (03.03.2025)
Boguszow-Gorce is located in Wałbrzyski, Poland within 50° 46' 0.12" N 16° 11' 60" E (50.7667, 16.2000) coordinates. The local time in Boguszow-Gorce is 05:36 (04.03.2025)
The calculated flying distance from Boguszow-Gorce to Boguszow-Gorce is 4,767.29 miles which is equal to 7,672.21 km.
Evansville, Indiana, United States
Related Distances from Evansville
Boguszow-Gorce, Wałbrzyski, Poland