Distance from Evansville to Celakovice
The shortest distance (air line) between Evansville and Celakovice is 4,738.51 mi (7,625.89 km).
How far is Evansville from Celakovice
Evansville is located in Indiana, United States within 37° 59' 17.16" N -88° 27' 57.24" W (37.9881, -87.5341) coordinates. The local time in Evansville is 14:10 (22.01.2025)
Celakovice is located in Středočeský kraj, Czechia within 50° 9' 38.16" N 14° 45' 0" E (50.1606, 14.7500) coordinates. The local time in Celakovice is 21:10 (22.01.2025)
The calculated flying distance from Celakovice to Celakovice is 4,738.51 miles which is equal to 7,625.89 km.
Evansville, Indiana, United States
Related Distances from Evansville
Celakovice, Středočeský kraj, Czechia