Distance from Evansville to Cesky Tesin
The shortest distance (air line) between Evansville and Cesky Tesin is 4,895.45 mi (7,878.47 km).
How far is Evansville from Cesky Tesin
Evansville is located in Indiana, United States within 37° 59' 17.16" N -88° 27' 57.24" W (37.9881, -87.5341) coordinates. The local time in Evansville is 17:09 (22.01.2025)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 00:09 (23.01.2025)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 4,895.45 miles which is equal to 7,878.47 km.
Evansville, Indiana, United States
Related Distances from Evansville
Cesky Tesin, Moravskoslezský kraj, Czechia