Distance from Evansville to Janow Lubelski
The shortest distance (air line) between Evansville and Janow Lubelski is 4,986.69 mi (8,025.30 km).
How far is Evansville from Janow Lubelski
Evansville is located in Indiana, United States within 37° 59' 17.16" N -88° 27' 57.24" W (37.9881, -87.5341) coordinates. The local time in Evansville is 04:02 (04.03.2025)
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 11:02 (04.03.2025)
The calculated flying distance from Janow Lubelski to Janow Lubelski is 4,986.69 miles which is equal to 8,025.30 km.
Evansville, Indiana, United States
Related Distances from Evansville
Janow Lubelski, Puławski, Poland