Distance from Evansville to Scherpenheuvel
The shortest distance (air line) between Evansville and Scherpenheuvel is 4,340.78 mi (6,985.81 km).
How far is Evansville from Scherpenheuvel
Evansville is located in Indiana, United States within 37° 59' 17.16" N -88° 27' 57.24" W (37.9881, -87.5341) coordinates. The local time in Evansville is 11:06 (08.02.2025)
Scherpenheuvel is located in Arr. Leuven, Belgium within 51° 0' 37.08" N 4° 58' 22.08" E (51.0103, 4.9728) coordinates. The local time in Scherpenheuvel is 18:06 (08.02.2025)
The calculated flying distance from Scherpenheuvel to Scherpenheuvel is 4,340.78 miles which is equal to 6,985.81 km.
Evansville, Indiana, United States
Related Distances from Evansville
Scherpenheuvel, Arr. Leuven, Belgium