Distance from Evansville to Sint-Pieters-Leeuw
The shortest distance (air line) between Evansville and Sint-Pieters-Leeuw is 4,320.11 mi (6,952.55 km).
How far is Evansville from Sint-Pieters-Leeuw
Evansville is located in Indiana, United States within 37° 59' 17.16" N -88° 27' 57.24" W (37.9881, -87.5341) coordinates. The local time in Evansville is 21:57 (01.02.2025)
Sint-Pieters-Leeuw is located in Arr. Halle-Vilvoorde, Belgium within 50° 46' 59.88" N 4° 15' 0" E (50.7833, 4.2500) coordinates. The local time in Sint-Pieters-Leeuw is 04:57 (02.02.2025)
The calculated flying distance from Sint-Pieters-Leeuw to Sint-Pieters-Leeuw is 4,320.11 miles which is equal to 6,952.55 km.
Evansville, Indiana, United States
Related Distances from Evansville
Sint-Pieters-Leeuw, Arr. Halle-Vilvoorde, Belgium