Distance from Evansville to Tomaszow Lubelski
The shortest distance (air line) between Evansville and Tomaszow Lubelski is 5,032.32 mi (8,098.73 km).
How far is Evansville from Tomaszow Lubelski
Evansville is located in Indiana, United States within 37° 59' 17.16" N -88° 27' 57.24" W (37.9881, -87.5341) coordinates. The local time in Evansville is 16:30 (04.03.2025)
Tomaszow Lubelski is located in Chełmsko-zamojski, Poland within 50° 27' 0" N 23° 25' 0.12" E (50.4500, 23.4167) coordinates. The local time in Tomaszow Lubelski is 23:30 (04.03.2025)
The calculated flying distance from Tomaszow Lubelski to Tomaszow Lubelski is 5,032.32 miles which is equal to 8,098.73 km.
Evansville, Indiana, United States
Related Distances from Evansville
Tomaszow Lubelski, Chełmsko-zamojski, Poland