Distance from Fargo to Diepenbeek
The shortest distance (air line) between Fargo and Diepenbeek is 4,259.31 mi (6,854.70 km).
How far is Fargo from Diepenbeek
Fargo is located in North Dakota, United States within 46° 51' 54.36" N -97° 10' 14.88" W (46.8651, -96.8292) coordinates. The local time in Fargo is 09:33 (01.02.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 16:33 (01.02.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 4,259.31 miles which is equal to 6,854.70 km.
Fargo, North Dakota, United States
Related Distances from Fargo
Diepenbeek, Arr. Hasselt, Belgium