Distance from Fargo to Mercato San Severino
The shortest distance (air line) between Fargo and Mercato San Severino is 5,069.64 mi (8,158.80 km).
How far is Fargo from Mercato San Severino
Fargo is located in North Dakota, United States within 46° 51' 54.36" N -97° 10' 14.88" W (46.8651, -96.8292) coordinates. The local time in Fargo is 05:37 (23.02.2025)
Mercato San Severino is located in Salerno, Italy within 40° 46' 59.88" N 14° 46' 0.12" E (40.7833, 14.7667) coordinates. The local time in Mercato San Severino is 12:37 (23.02.2025)
The calculated flying distance from Mercato San Severino to Mercato San Severino is 5,069.64 miles which is equal to 8,158.80 km.
Fargo, North Dakota, United States
Related Distances from Fargo
Mercato San Severino, Salerno, Italy