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      Distance from Fargo to San Sebastian de los Reyes

      The shortest distance (air line) between Fargo and San Sebastian de los Reyes is 4,391.16 mi (7,066.88 km).

      How far is Fargo from San Sebastian de los Reyes

      Fargo is located in North Dakota, United States within 46° 51' 54.36" N -97° 10' 14.88" W (46.8651, -96.8292) coordinates. The local time in Fargo is 20:30 (08.03.2025)

      San Sebastian de los Reyes is located in Madrid, Spain within 40° 32' 48.84" N -4° 22' 27.12" W (40.5469, -3.6258) coordinates. The local time in San Sebastian de los Reyes is 03:30 (09.03.2025)

      The calculated flying distance from San Sebastian de los Reyes to San Sebastian de los Reyes is 4,391.16 miles which is equal to 7,066.88 km.

      Fargo, North Dakota, United States

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      San Sebastian de los Reyes, Madrid, Spain

      Related Distances to San Sebastian de los Reyes