Distance from Faribault to Bad Sassendorf
The shortest distance (air line) between Faribault and Bad Sassendorf is 4,330.76 mi (6,969.68 km).
How far is Faribault from Bad Sassendorf
Faribault is located in Minnesota, United States within 44° 17' 58.56" N -94° 43' 15.96" W (44.2996, -93.2789) coordinates. The local time in Faribault is 12:03 (05.02.2025)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 19:03 (05.02.2025)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 4,330.76 miles which is equal to 6,969.68 km.
Faribault, Minnesota, United States
Related Distances from Faribault
Bad Sassendorf, Soest, Germany