Distance from Faribault to Mercato San Severino
The shortest distance (air line) between Faribault and Mercato San Severino is 5,060.53 mi (8,144.14 km).
How far is Faribault from Mercato San Severino
Faribault is located in Minnesota, United States within 44° 17' 58.56" N -94° 43' 15.96" W (44.2996, -93.2789) coordinates. The local time in Faribault is 22:32 (24.02.2025)
Mercato San Severino is located in Salerno, Italy within 40° 46' 59.88" N 14° 46' 0.12" E (40.7833, 14.7667) coordinates. The local time in Mercato San Severino is 05:32 (25.02.2025)
The calculated flying distance from Mercato San Severino to Mercato San Severino is 5,060.53 miles which is equal to 8,144.14 km.
Faribault, Minnesota, United States
Related Distances from Faribault
Mercato San Severino, Salerno, Italy