Distance from Faribault to Monte San Savino
The shortest distance (air line) between Faribault and Monte San Savino is 4,826.35 mi (7,767.27 km).
How far is Faribault from Monte San Savino
Faribault is located in Minnesota, United States within 44° 17' 58.56" N -94° 43' 15.96" W (44.2996, -93.2789) coordinates. The local time in Faribault is 22:28 (24.02.2025)
Monte San Savino is located in Arezzo, Italy within 43° 19' 59.88" N 11° 43' 59.88" E (43.3333, 11.7333) coordinates. The local time in Monte San Savino is 05:28 (25.02.2025)
The calculated flying distance from Monte San Savino to Monte San Savino is 4,826.35 miles which is equal to 7,767.27 km.
Faribault, Minnesota, United States
Related Distances from Faribault
Monte San Savino, Arezzo, Italy