Distance from Faribault to Peekskill
The shortest distance (air line) between Faribault and Peekskill is 1,000.67 mi (1,610.42 km).
How far is Faribault from Peekskill
Faribault is located in Minnesota, United States within 44° 17' 58.56" N -94° 43' 15.96" W (44.2996, -93.2789) coordinates. The local time in Faribault is 14:58 (04.10.2025)
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 15:58 (04.10.2025)
The calculated flying distance from Peekskill to Peekskill is 1,000.67 miles which is equal to 1,610.42 km.
Faribault, Minnesota, United States
Related Distances from Faribault
Peekskill, New York, United States