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      Distance from Faribault to San Juan de Aznalfarache

      The shortest distance (air line) between Faribault and San Juan de Aznalfarache is 4,365.96 mi (7,026.33 km).

      How far is Faribault from San Juan de Aznalfarache

      Faribault is located in Minnesota, United States within 44° 17' 58.56" N -94° 43' 15.96" W (44.2996, -93.2789) coordinates. The local time in Faribault is 17:05 (10.03.2025)

      San Juan de Aznalfarache is located in Sevilla, Spain within 37° 22' 0.12" N -7° 58' 59.88" W (37.3667, -6.0167) coordinates. The local time in San Juan de Aznalfarache is 00:05 (11.03.2025)

      The calculated flying distance from San Juan de Aznalfarache to San Juan de Aznalfarache is 4,365.96 miles which is equal to 7,026.33 km.

      Faribault, Minnesota, United States

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      San Juan de Aznalfarache, Sevilla, Spain

      Related Distances to San Juan de Aznalfarache