Distance from Faribault to San Severino Marche
The shortest distance (air line) between Faribault and San Severino Marche is 4,884.42 mi (7,860.71 km).
How far is Faribault from San Severino Marche
Faribault is located in Minnesota, United States within 44° 17' 58.56" N -94° 43' 15.96" W (44.2996, -93.2789) coordinates. The local time in Faribault is 18:32 (25.02.2025)
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 01:32 (26.02.2025)
The calculated flying distance from San Severino Marche to San Severino Marche is 4,884.42 miles which is equal to 7,860.71 km.
Faribault, Minnesota, United States
Related Distances from Faribault
San Severino Marche, Macerata, Italy