Distance from Faribault to Sassenheim
The shortest distance (air line) between Faribault and Sassenheim is 4,179.63 mi (6,726.47 km).
How far is Faribault from Sassenheim
Faribault is located in Minnesota, United States within 44° 17' 58.56" N -94° 43' 15.96" W (44.2996, -93.2789) coordinates. The local time in Faribault is 05:55 (28.02.2025)
Sassenheim is located in Agglomeratie Leiden en Bollenstreek, Netherlands within 52° 13' 32.88" N 4° 31' 21" E (52.2258, 4.5225) coordinates. The local time in Sassenheim is 12:55 (28.02.2025)
The calculated flying distance from Sassenheim to Sassenheim is 4,179.63 miles which is equal to 6,726.47 km.
Faribault, Minnesota, United States
Related Distances from Faribault
Sassenheim, Agglomeratie Leiden en Bollenstreek, Netherlands