Distance from Faribault to Seagoville
The shortest distance (air line) between Faribault and Seagoville is 823.68 mi (1,325.59 km).
How far is Faribault from Seagoville
Faribault is located in Minnesota, United States within 44° 17' 58.56" N -94° 43' 15.96" W (44.2996, -93.2789) coordinates. The local time in Faribault is 05:22 (06.10.2025)
Seagoville is located in Texas, United States within 32° 39' 10.8" N -97° 27' 15.84" W (32.6530, -96.5456) coordinates. The local time in Seagoville is 05:22 (06.10.2025)
The calculated flying distance from Seagoville to Seagoville is 823.68 miles which is equal to 1,325.59 km.
Faribault, Minnesota, United States
Related Distances from Faribault
Seagoville, Texas, United States