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      Distance from Farragut to Villanueva de la Canada

      The shortest distance (air line) between Farragut and Villanueva de la Canada is 4,213.15 mi (6,780.40 km).

      How far is Farragut from Villanueva de la Canada

      Farragut is located in Tennessee, United States within 35° 52' 23.16" N -85° 49' 4.44" W (35.8731, -84.1821) coordinates. The local time in Farragut is 05:48 (06.03.2025)

      Villanueva de la Canada is located in Madrid, Spain within 40° 27' 0" N -4° 1' 0.12" W (40.4500, -3.9833) coordinates. The local time in Villanueva de la Canada is 11:48 (06.03.2025)

      The calculated flying distance from Villanueva de la Canada to Villanueva de la Canada is 4,213.15 miles which is equal to 6,780.40 km.

      Farragut, Tennessee, United States

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      Villanueva de la Canada, Madrid, Spain

      Related Distances to Villanueva de la Canada