Distance from Fayetteville to Aleksandrow Kujawski
The shortest distance (air line) between Fayetteville and Aleksandrow Kujawski is 5,095.10 mi (8,199.76 km).
How far is Fayetteville from Aleksandrow Kujawski
Fayetteville is located in Arkansas, United States within 36° 4' 17.04" N -95° 50' 2.04" W (36.0714, -94.1661) coordinates. The local time in Fayetteville is 14:56 (12.03.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 21:56 (12.03.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 5,095.10 miles which is equal to 8,199.76 km.
Fayetteville, Arkansas, United States
Related Distances from Fayetteville
Aleksandrow Kujawski, Włocławski, Poland