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      Distance from Fergus Falls to San Pancrazio Salentino

      The shortest distance (air line) between Fergus Falls and San Pancrazio Salentino is 5,196.10 mi (8,362.31 km).

      How far is Fergus Falls from San Pancrazio Salentino

      Fergus Falls is located in Minnesota, United States within 46° 17' 7.44" N -97° 55' 27.12" W (46.2854, -96.0758) coordinates. The local time in Fergus Falls is 02:48 (23.02.2025)

      San Pancrazio Salentino is located in Brindisi, Italy within 40° 25' 0.12" N 17° 49' 59.88" E (40.4167, 17.8333) coordinates. The local time in San Pancrazio Salentino is 09:48 (23.02.2025)

      The calculated flying distance from San Pancrazio Salentino to San Pancrazio Salentino is 5,196.10 miles which is equal to 8,362.31 km.

      Fergus Falls, Minnesota, United States

      Related Distances from Fergus Falls

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      Fergus Falls to New York (New York)1,170.98 mi (1,884.51 km)
      Fergus Falls to Brooklyn (New York)1,171.20 mi (1,884.86 km)
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      Fergus Falls to Portland (Oregon)1,272.56 mi (2,047.98 km)
      Fergus Falls to Riverside (California)1,405.48 mi (2,261.90 km)
      Fergus Falls to Los Angeles (California)1,439.51 mi (2,316.67 km)
      Fergus Falls to San Diego (California)1,448.32 mi (2,330.84 km)
      Fergus Falls to Tampa (Florida)1,465.17 mi (2,357.97 km)
      Fergus Falls to San Francisco (California)1,467.34 mi (2,361.45 km)
      Fergus Falls to Miami (Florida)1,663.94 mi (2,677.86 km)
      Fergus Falls to Minneapolis (Minnesota)163.55 mi (263.20 km)
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      San Pancrazio Salentino, Brindisi, Italy

      Related Distances to San Pancrazio Salentino