Distance from Fergus Falls to San Severino Marche
The shortest distance (air line) between Fergus Falls and San Severino Marche is 4,891.17 mi (7,871.58 km).
How far is Fergus Falls from San Severino Marche
Fergus Falls is located in Minnesota, United States within 46° 17' 7.44" N -97° 55' 27.12" W (46.2854, -96.0758) coordinates. The local time in Fergus Falls is 03:04 (23.02.2025)
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 10:04 (23.02.2025)
The calculated flying distance from San Severino Marche to San Severino Marche is 4,891.17 miles which is equal to 7,871.58 km.
Fergus Falls, Minnesota, United States
Related Distances from Fergus Falls
San Severino Marche, Macerata, Italy