Distance from Fernandina Beach to East Patchogue
The shortest distance (air line) between Fernandina Beach and East Patchogue is 844.03 mi (1,358.33 km).
How far is Fernandina Beach from East Patchogue
Fernandina Beach is located in Florida, United States within 30° 39' 25.56" N -82° 32' 56.04" W (30.6571, -81.4511) coordinates. The local time in Fernandina Beach is 16:07 (10.12.2025)
East Patchogue is located in New York, United States within 40° 46' 13.44" N -73° 1' 5.88" W (40.7704, -72.9817) coordinates. The local time in East Patchogue is 16:07 (10.12.2025)
The calculated flying distance from East Patchogue to East Patchogue is 844.03 miles which is equal to 1,358.33 km.
Fernandina Beach, Florida, United States
Related Distances from Fernandina Beach
East Patchogue, New York, United States