Distance from Fernandina Beach to Jefferson Valley-Yorktown
The shortest distance (air line) between Fernandina Beach and Jefferson Valley-Yorktown is 850.91 mi (1,369.40 km).
How far is Fernandina Beach from Jefferson Valley-Yorktown
Fernandina Beach is located in Florida, United States within 30° 39' 25.56" N -82° 32' 56.04" W (30.6571, -81.4511) coordinates. The local time in Fernandina Beach is 06:41 (17.12.2025)
Jefferson Valley-Yorktown is located in New York, United States within 41° 19' 4.8" N -74° 11' 57.12" W (41.3180, -73.8008) coordinates. The local time in Jefferson Valley-Yorktown is 06:41 (17.12.2025)
The calculated flying distance from Jefferson Valley-Yorktown to Jefferson Valley-Yorktown is 850.91 miles which is equal to 1,369.40 km.
Fernandina Beach, Florida, United States
Related Distances from Fernandina Beach
Jefferson Valley-Yorktown, New York, United States