Distance from Fernley to Sapulpa
The shortest distance (air line) between Fernley and Sapulpa is 1,280.79 mi (2,061.24 km).
How far is Fernley from Sapulpa
Fernley is located in Nevada, United States within 39° 33' 45.72" N -120° 48' 33.84" W (39.5627, -119.1906) coordinates. The local time in Fernley is 02:29 (05.05.2025)
Sapulpa is located in Oklahoma, United States within 36° 0' 32.76" N -97° 53' 58.92" W (36.0091, -96.1003) coordinates. The local time in Sapulpa is 04:29 (05.05.2025)
The calculated flying distance from Sapulpa to Sapulpa is 1,280.79 miles which is equal to 2,061.24 km.
Fernley, Nevada, United States
Related Distances from Fernley
Sapulpa, Oklahoma, United States