Distance from Findlay to Sveti Ivan Zelina
The shortest distance (air line) between Findlay and Sveti Ivan Zelina is 4,666.36 mi (7,509.78 km).
How far is Findlay from Sveti Ivan Zelina
Findlay is located in Ohio, United States within 41° 2' 48.84" N -84° 21' 43.56" W (41.0469, -83.6379) coordinates. The local time in Findlay is 11:49 (22.01.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 17:49 (22.01.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 4,666.36 miles which is equal to 7,509.78 km.
Related Distances from Findlay
Sveti Ivan Zelina, Zagrebačka županija, Croatia