Distance from Florida Ridge to Boortmeerbeek
The shortest distance (air line) between Florida Ridge and Boortmeerbeek is 4,551.07 mi (7,324.24 km).
How far is Florida Ridge from Boortmeerbeek
Florida Ridge is located in Florida, United States within 27° 34' 49.8" N -81° 36' 54.72" W (27.5805, -80.3848) coordinates. The local time in Florida Ridge is 19:02 (01.02.2025)
Boortmeerbeek is located in Arr. Leuven, Belgium within 50° 58' 59.88" N 4° 34' 0.12" E (50.9833, 4.5667) coordinates. The local time in Boortmeerbeek is 01:02 (02.02.2025)
The calculated flying distance from Boortmeerbeek to Boortmeerbeek is 4,551.07 miles which is equal to 7,324.24 km.
Florida Ridge, Florida, United States
Related Distances from Florida Ridge
Boortmeerbeek, Arr. Leuven, Belgium