Distance from Florida Ridge to Janow Lubelski
The shortest distance (air line) between Florida Ridge and Janow Lubelski is 5,283.29 mi (8,502.64 km).
How far is Florida Ridge from Janow Lubelski
Florida Ridge is located in Florida, United States within 27° 34' 49.8" N -81° 36' 54.72" W (27.5805, -80.3848) coordinates. The local time in Florida Ridge is 22:21 (26.02.2025)
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 04:21 (27.02.2025)
The calculated flying distance from Janow Lubelski to Janow Lubelski is 5,283.29 miles which is equal to 8,502.64 km.
Florida Ridge, Florida, United States
Related Distances from Florida Ridge
Janow Lubelski, Puławski, Poland