Distance from Florida Ridge to Sint-Andries
The shortest distance (air line) between Florida Ridge and Sint-Andries is 4,489.20 mi (7,224.66 km).
How far is Florida Ridge from Sint-Andries
Florida Ridge is located in Florida, United States within 27° 34' 49.8" N -81° 36' 54.72" W (27.5805, -80.3848) coordinates. The local time in Florida Ridge is 08:55 (02.02.2025)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 14:55 (02.02.2025)
The calculated flying distance from Sint-Andries to Sint-Andries is 4,489.20 miles which is equal to 7,224.66 km.
Florida Ridge, Florida, United States
Related Distances from Florida Ridge
Sint-Andries, Arr. Brugge, Belgium