Distance from Florida Ridge to Steenokkerzeel
The shortest distance (air line) between Florida Ridge and Steenokkerzeel is 4,549.73 mi (7,322.09 km).
How far is Florida Ridge from Steenokkerzeel
Florida Ridge is located in Florida, United States within 27° 34' 49.8" N -81° 36' 54.72" W (27.5805, -80.3848) coordinates. The local time in Florida Ridge is 09:35 (02.02.2025)
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 15:35 (02.02.2025)
The calculated flying distance from Steenokkerzeel to Steenokkerzeel is 4,549.73 miles which is equal to 7,322.09 km.
Florida Ridge, Florida, United States
Related Distances from Florida Ridge
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium