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      Distance from Florida Ridge to Villanueva de la Canada

      The shortest distance (air line) between Florida Ridge and Villanueva de la Canada is 4,330.73 mi (6,969.63 km).

      How far is Florida Ridge from Villanueva de la Canada

      Florida Ridge is located in Florida, United States within 27° 34' 49.8" N -81° 36' 54.72" W (27.5805, -80.3848) coordinates. The local time in Florida Ridge is 18:29 (06.03.2025)

      Villanueva de la Canada is located in Madrid, Spain within 40° 27' 0" N -4° 1' 0.12" W (40.4500, -3.9833) coordinates. The local time in Villanueva de la Canada is 00:29 (07.03.2025)

      The calculated flying distance from Villanueva de la Canada to Villanueva de la Canada is 4,330.73 miles which is equal to 6,969.63 km.

      Florida Ridge, Florida, United States

      Related Distances from Florida Ridge

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      Florida Ridge to New York (New York)977.74 mi (1,573.53 km)
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      Florida Ridge to Detroit (Michigan)1,034.13 mi (1,664.27 km)
      Florida Ridge to Dallas (Texas)1,041.14 mi (1,675.56 km)
      Florida Ridge to Chicago (Illinois)1,067.76 mi (1,718.39 km)
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      Florida Ridge to Phoenix (Arizona)1,922.92 mi (3,094.64 km)
      Florida Ridge to Las Vegas (Nevada)2,118.67 mi (3,409.67 km)
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      Florida Ridge to Riverside (California)2,228.49 mi (3,586.41 km)
      Florida Ridge to Los Angeles (California)2,286.65 mi (3,680.00 km)
      Florida Ridge to San Francisco (California)2,522.41 mi (4,059.43 km)
      Florida Ridge to Portland (Oregon)2,613.41 mi (4,205.88 km)
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      Villanueva de la Canada, Madrid, Spain

      Related Distances to Villanueva de la Canada