Distance from Fountain Valley to Cesky Tesin
The shortest distance (air line) between Fountain Valley and Cesky Tesin is 6,087.09 mi (9,796.23 km).
How far is Fountain Valley from Cesky Tesin
Fountain Valley is located in California, United States within 33° 42' 37.8" N -118° 2' 54.96" W (33.7105, -117.9514) coordinates. The local time in Fountain Valley is 11:56 (24.04.2025)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 20:56 (24.04.2025)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 6,087.09 miles which is equal to 9,796.23 km.
Fountain Valley, California, United States
Related Distances from Fountain Valley
Cesky Tesin, Moravskoslezský kraj, Czechia