Distance from Franklin Lakes to Scherpenheuvel
The shortest distance (air line) between Franklin Lakes and Scherpenheuvel is 3,675.21 mi (5,914.68 km).
How far is Franklin Lakes from Scherpenheuvel
Franklin Lakes is located in New Jersey, United States within 41° 0' 30.96" N -75° 47' 30.12" W (41.0086, -74.2083) coordinates. The local time in Franklin Lakes is 21:05 (09.02.2025)
Scherpenheuvel is located in Arr. Leuven, Belgium within 51° 0' 37.08" N 4° 58' 22.08" E (51.0103, 4.9728) coordinates. The local time in Scherpenheuvel is 03:05 (10.02.2025)
The calculated flying distance from Scherpenheuvel to Scherpenheuvel is 3,675.21 miles which is equal to 5,914.68 km.
Franklin Lakes, New Jersey, United States
Related Distances from Franklin Lakes
Scherpenheuvel, Arr. Leuven, Belgium