Distance from Franklin Lakes to Steenokkerzeel
The shortest distance (air line) between Franklin Lakes and Steenokkerzeel is 3,658.86 mi (5,888.37 km).
How far is Franklin Lakes from Steenokkerzeel
Franklin Lakes is located in New Jersey, United States within 41° 0' 30.96" N -75° 47' 30.12" W (41.0086, -74.2083) coordinates. The local time in Franklin Lakes is 20:31 (09.02.2025)
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 02:31 (10.02.2025)
The calculated flying distance from Steenokkerzeel to Steenokkerzeel is 3,658.86 miles which is equal to 5,888.37 km.
Franklin Lakes, New Jersey, United States
Related Distances from Franklin Lakes
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium