Distance from Franklin Square to Steenokkerzeel
The shortest distance (air line) between Franklin Square and Steenokkerzeel is 3,650.86 mi (5,875.49 km).
How far is Franklin Square from Steenokkerzeel
Franklin Square is located in New York, United States within 40° 42' 0.72" N -74° 19' 21" W (40.7002, -73.6775) coordinates. The local time in Franklin Square is 08:47 (04.06.2025)
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 14:47 (04.06.2025)
The calculated flying distance from Steenokkerzeel to Steenokkerzeel is 3,650.86 miles which is equal to 5,875.49 km.
Franklin Square, New York, United States
Related Distances from Franklin Square
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium